A thermodynamic system undergoes cyclic process ABCDA as shown in fig. The work done by the system in the cycle is:
Answer & explanation
Correct answer: option 4
Work done by the system in the cycle = Area under P – V curve & V – axis
For clockwise work done is positive ; For anticlockwise work done is negative
WADEA = \(\frac{1}{2} (2P_o - P_o) (2V_o - V_o)\)
WEBCE = - \(\frac{1}{2} (3P_o - 2P_o) (2V_o - V_o)\)
WEBCE - WADEA = 0