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-- Mathematics - Section B1
Determinants
The projection of the vector $\hat{i}+\hat{j}+\hat{k}$ on the vector $\hat{j}$ is :
0
1
2
-1
$\vec{v_1} = \hat{i}+\hat{j}+\hat{k}$
$\vec{v_2} = \hat{j}$
so projection of $\vec{v_1}$ on $\vec{v_2}$ is $\vec{v_1} . \vec{v_2}$
= 1