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The distance between the parallel planes $2x- y + 2z + 3 = 0 $ and $4x - 2y + 4z + 5 = 0 $is |
$\frac{1}{3}$ $\frac{2}{6}$ $\frac{2}{3}$ none of these |
$\frac{2}{6}$ |
The equations of two planes are $2x- y + 2z + 3 = 0 $ and $2x - y + 2z +\frac{5}{2}= 0.$ ∴ Required distance $= \frac{|3-\frac{5}{2}|}{\sqrt{4+1 + 4}}= \frac{1}{6}$ |
