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The fringe width in Young's double slit experiment is $2.4 × 10^{-4} m$, when red light of wavelength 6400 Å is used. The decrease in the fringe width, if light of wavelength 4000 Å is used instead of red light, will be |
$0.9 × 10^{-4} m$ $9 × 10^{-4} m$ $1.5 × 10^{-4} m$ $2 × 10^{-4} m$ |
$0.9 × 10^{-4} m$ |
The correct answer is Option (1) → $0.9 × 10^{-4} m$ |
