The circles of same radius 13 cm intersect each other at A and B. If AB = 10 cm, then the distance between their centres is :
Answer & explanation
Correct answer: option 3
As we can see the radius of the circle = 13
and the distance of AO = 5
So, according to the pythagoras theorem =
AM2 = AO2 + MO2
(13)2 = (5)2 + MO2
169 - 25 = MO2
144 = MO2
MO = \(\sqrt {144}\) = 12
So the difference between their centers = MN = 12 × 2 = 24