Practicing Success
The circles of same radius 13 cm intersect each other at A and B. If AB = 10 cm, then the distance between their centres is : |
18 cm 12 cm 24 cm 26 cm |
24 cm |
As we can see the radius of the circle = 13 and the distance of AO = 5 So, according to the pythagoras theorem = AM2 = AO2 + MO2 (13)2 = (5)2 + MO2 169 - 25 = MO2 144 = MO2 MO = \(\sqrt {144}\) = 12 So the difference between their centers = MN = 12 × 2 = 24 |