Practicing Success
Initial angular velocity of a circular disc of mass M is ω1 Then two spheres of mass m are attached gently two diametrically opposite points on the edge of the disc what is the final angular velocity of the disc? |
[(M + 4m) / M] ω1 [(M + m) / M] ω1 [M / (M + 2m)] ω1 [M / (M + 4m)] ω1 |
[M / (M + 2m)] ω1 |
Conservation of Angular Momentum : I1ω1 = I2ω2 ω2 = (I1 / I2)ω1 For circular disc : I = [(MR2) / 2] I1 = [(MR2) / 2] when two spheres of masses are attached then total mass is M + 2m I2 = [(M + 2m) / 2]R2 hence ω2 = [{(MR2) / 2} / {{(M + 2m) / 2}]R2}](ω1) = [M / (M + 2m)]ω1 |