Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

System of Particle and Rotational Motion

Question:

Initial angular velocity of a circular disc of mass M is ω1 Then two spheres of mass m are attached gently two diametrically opposite points on the edge of the disc what is the final angular velocity of the disc? 

Options:

[(M + 4m) / M] ω1  

[(M + m) / M] ω1  

[M / (M + 2m)] ω1  

[M / (M + 4m)] ω1  

Correct Answer:

[M / (M + 2m)] ω1  

Explanation:

Conservation of Angular Momentum : I1ω1 = I2ω2 

ω2 = (I1 / I21 

For circular disc : I = [(MR2) / 2]

I1 = [(MR2) / 2]

when two spheres of masses are attached then total mass is M + 2m

I2 = [(M + 2m) / 2]R2 

hence ω2 = [{(MR2) / 2} / {{(M + 2m) / 2}]R2}](ω1)

= [M / (M + 2m)]ω1­­