Practicing Success
Two bodies of masses m and M are placed a distance d apart. The gravitational potential at the position where the gravitational field due to them is zero is V, then : |
V = -G/d (m +M) V = -G/d (√m+√m)2 V = -Gm/d V= -Gm/d |
V = -G/d (m +M) |
If P is the point of zero intensity, then : \(x = \frac{\sqrt{M}}{\sqrt{M} + \sqrt{m}}.d \text{ and }\) \(d - x = d - \frac{\sqrt{M}}{\sqrt{M} + \sqrt{m}}.d \text{ and }\) Now potential at point P, \(V = V_1 + V_2\) \(V = -\frac{GM}{x} - \frac{GM}{d-x}\) \(V = - \frac{G}{d} (\sqrt{m} + \sqrt{M})^2\) |