Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Indefinite Integration

Question:

$\int(1-x)^{23} x d x$

Options:

$\frac{x^{23}}{23}+\frac{x^{24}}{24}+c$

$\frac{(x-1)^{23}}{23}+\frac{(x-1)^{24}}{24}+C$

$\frac{(1-x)^{25}}{25}-\frac{(1-x)^{24}}{24}+c$

none of these

Correct Answer:

$\frac{(1-x)^{25}}{25}-\frac{(1-x)^{24}}{24}+c$

Explanation:

Put (1 –x) = t

–dx = dt

$\int-d t t^{23}(1-t)=\int\left(t^{24}-t^{23}\right) d t$

$=\frac{t^{25}}{25}-\frac{t^{24}}{24}+c=\frac{(1-x)^{25}}{25}-\frac{(1-x)^{24}}{24}+c$

Hence (3) is the correct answer.