Name the particle 'X' emitted in the nuclear reaction given below -

${_{11}^{22}Na} → {_{11}^{22}Ne}+v+X$

Positron

The correct answer is Option (3) → Positron

The reaction is,

${_{11}^{22}Na} → {_{11}^{22}Ne}+v+X$

A positron is emitted because, the atomic number has decreased by 1, which indicates the emission of a positive charge (positron).