Practicing Success
Practicing Success
CUET Preparation Today
Two independent events A and B are such that P(A) = \(\frac{1}{2}\) and P(B) = \(\frac{1}{3}\), the P(A|B) = |
\(\frac{1}{3}\) \(\frac{1}{2}\) \(\frac{2}{3}\) 1 |
\(\frac{1}{2}\) |
\(P(A) = \frac{1}{2}\), \(P(B) =\frac{1}{3}\) $∴ P(\frac{A}{B})=\frac{P(A∩B)}{P(B)}=\frac{\frac{1}{2}×\frac{1}{3}}{\frac{1}{3}}=\frac{1}{2}$ Option 2 is correct. |
