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The maximum area of a rectangle whose two vertices lie on th x-axis and two on the curve y = 3 - |x|, -3\(\leq x \leq \) 3 is : |
9 \(\frac{9}{2}\) 3 none of these |
\(\frac{9}{2}\) |
Area : A = 2x (3 - x) A' = 2x (3 - x) - 2x x = 3/2 Maximum area of the rectangle occurs when x = 3/2 maximum area = 2.[3/2][3-\frac{3}{2}\)] = 9/2 sq. units |
