The energy of the highest energy photon of Balmer series of hydrogen spectrum is close to
Answer & explanation
Correct answer: option 2
$E=13.6\left[\frac{1}{n_1^2}-\frac{1}{n_2^2}\right]$. For highest energy in Balmer series $n_1=2$ and $n_2=\infty \Rightarrow E=13.6\left[\frac{1}{(2)^2}-\frac{1}{(\infty)^2}\right]$ = 3.4 eV