Find the curved surface area of a solid cylinder whose radius of base is 14 cm and volume is 7392 cm3. [Use π = $\frac{22}{7}$]
Answer & explanation
Correct answer: option 2
We know that,
Curved surface area of a cylinder = 2πrh
Volume of a cylinder = πr2h
We have,
Radius = 14 cm
Volume = 7392 cm3
\(\frac{22}{7}\) × 142 × H = 7392
= H = 7392 × \(\frac{7}{ 22 × 196}\)
= H = 12
Now, the curved surface area of a solid cylinder = 2 × \(\frac{22}{ 7}\) × 14 × 12 = 1056 cm2