Practicing Success
Practicing Success
CUET Preparation Today
If $f(x)\left\{\begin{matrix}ax^2+b:&x≤0\\x^2:&x>0\end{matrix}\right.$ possesses derivative at x = 0, then: |
a = 0, b = 0 a > 0, b = 0 a ∈ R, b = 0 None of these |
None of these |
$\underset{x→0^+}{\lim}f(x)=\underset{x→0^-}{\lim}f(x)$ $⇒ b = 0$ $\underset{x→0^+}{\lim}f'(x)=\underset{x→0^-}{\lim}f'(x)$ so $2x =2ax$ $⇒ a = 1$ $a=1,b=0$ |
