Practicing Success
The value of $tan^{-1}\begin{Bmatrix}2cos\left(2sin^{-1}\frac{1}{2}\right)\end{Bmatrix},$ is |
$\frac{\pi}{4}$ $\frac{-\pi}{4}$ $\frac{3\pi}{4}$ $-\frac{3\pi}{4}$ |
$\frac{\pi}{4}$ |
We know that $sin^{-1}\frac{1}{2}=\frac{\pi}{6}.$ $∴ tan^{-1}\begin{Bmatrix}2 cos \left(2sin^{-1}\frac{1}{2}\right)\end{Bmatrix}$ $= tan^{-1}\begin{Bmatrix}2cos \left(2× \frac{\pi}{6}\right)\end{Bmatrix}= tan^{-1}\left(2cos\frac{\pi}{3}\right)$ $=tan^{-1}\left(2 × \frac{1}{2}\right) = tan^{-1} =\frac{\pi}{4}$ |