Practicing Success
The vectors \(\vec{a}\)= (2\(\hat{i}\) -3\(\hat{j}\)+ 4\(\hat{k}\)) and \(\vec{b}\)= (-4\(\hat{i}\) + 6\(\hat{j}\)- 8\(\hat{k}\)) are- |
Collinear Non-collinear May or may not be collinear None of these |
Collinear |
We have \(\vec{a}\)= (2\(\hat{i}\) -3\(\hat{j}\)+ 4\(\hat{k}\)) and \(\vec{b}\)= (-4\(\hat{i}\) + 6\(\hat{j}\)- 8\(\hat{k}\)) It is observed that \(\vec{b}\)= (-4\(\hat{i}\) + 6\(\hat{j}\)- 8\(\hat{k}\)) = -2 (2 \(\hat{i}\) -3\(\hat{j}\)+ 4\(\hat{k}\)) = -2 \(\vec{a}\) \(\vec{b}\) = λ \(\vec{a}\) where λ = -2 Hence, the given vectors are collinear.
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