The value of $sin^{-1}\left(sin(-600°)\right) is $
Answer & explanation
Correct answer: option 1
$sin^{-1}\left(sin(-600°)\right) =sin^{-1}\begin{Bmatrix}sin\left(-600×\frac{\pi}{180}\right)\end{Bmatrix}$
$sin^{-1}\begin{Bmatrix}sin\left(-\frac{10\pi}{3}\right)\end{Bmatrix}= -sin^{-1}-\left(-sin\frac{10\pi}{3}\right)$
$sin^{-1}\begin{Bmatrix}sin\left(3\pi +\frac{\pi}{3}\right)\end{Bmatrix}= sin^{-1}\begin{Bmatrix}-\left(-sin\frac{\pi}{3}\right)\end{Bmatrix}$
$= sin^{-1}\left(sin\frac{\pi}{3}\right) =\frac{\pi}{3}$