To a circle with centre at O, two tangents AP and AQ are drawn from an external point A. If the ∠PAQ = 80°, then the ∠POQ is :
Answer & explanation
Correct answer: option 4
We have,
∠PAQ = 80°
∠PAQ + ∠OPA + ∠OQA + ∠POQ = 360°
= 80° + 90° + 90° + ∠POQ = 360°
= ∠POQ = 360° - 260°
= ∠POQ = 100°