Practicing Success
To a circle with centre at O, two tangents AP and AQ are drawn from an external point A. If the ∠PAQ = 80°, then the ∠POQ is : |
90° 80° 70° 100° |
100° |
We have, ∠PAQ = 80° ∠PAQ + ∠OPA + ∠OQA + ∠POQ = 360° = 80° + 90° + 90° + ∠POQ = 360° = ∠POQ = 360° - 260° = ∠POQ = 100° |