If gh and gd be the accelerations due to gravity at a height h and at depth d, above and below the surface of earth respectively. Assuming h << R and d <<R and if gh = gd then,
Answer & explanation
Correct answer: option 2
$g\left(1-\frac{2 h}{R}\right) \cong g\left(1-\frac{d}{R}\right)$
⇒ d = 2h