If a = 355, b = 356, c = 357, then find the value of $a^3 + b^3 + c^3 - 3abc$.
Answer & explanation
Correct answer: option 4
a = 355
b = 356
c = 357
a3 + b3 + c3 - 3abc = \(\frac{1}{2}\) × (a + b + c) × [(a – b)2 + (b – c)2 + (c – a)2]
a3 + b3 + c3 - 3abc = \(\frac{1}{2}\) × (355 + 356 + 357) × [(355 – 356)2 + (356 – 357)2 + (357 – 355)2]
= \(\frac{1}{2}\) × (1068) × (1 + 1 + 4)
= 534 × 6
= 3204