Practicing Success
The corner points of the feasible region determined by system of linear constraints are (60, 0), (120, 0), (40, 20) and (60, 30). Let $z = ax + by, a, b>0$ be the objective function. Find condition on a and b so that the maximum of $z$ occurs at (120, 0) and (60, 30). |
$b=\frac{a}{3}$ $2b=a$ $2a=b$ $a=\frac{b}{3}$ |
$2a=b$ |
objective function $z = ax + by$ Maxima occurs at two points (120, 0) and (60, 30) $⇒z(120, 0)=z(60, 30)$ $⇒120a+0=60a+30b$ $⇒120a=60a+30b$ $60a=30b$ $2a=b$ |