In ΔABC, AB = AC, O is a point at BC such that BO = OC and OD is perpendicular to AB and OE is perpendicular to AC. If ∠BOD = 40°, then the measure of ∠AOE is ?
Answer & explanation
Correct answer: option 1
In ΔBOD
∠DBO = 180° - 90° - 40° = 50°
AB = AC
∴ ∠ABO = ∠ACO = 50°
In ΔCOE
∠EOC = 180° - 50° - 90° = 40°
∠DOE = 180° - 80° = 100°
\(∠AOE=\frac{100°}{2}=50°\)