The area of a sector of a circle is 88 sq. cm., and the angle of the sector is 45°. Find the radius of the circle. (Use $л=\frac{22}{7}$)

$4\sqrt{14}$ cm

Let the radius of the circle be P cm.

According to the question,

⇒ (\(\Pi \) x \( {P }^{ 2} \)) x \(\frac{45}{360}\) = 88

⇒ (\(\frac{22}{7}\) x \( {P }^{ 2} \)) x \(\frac{1}{8}\) = 88

⇒ \( {P }^{ 2} \) = (4 x 7 x 8)

⇒ \( {P }^{ 2} \) = 4\(\sqrt { 14}\) cm

Therefore, the radius of the circle is 4\(\sqrt { 14}\) cm.