The Brewster’s angle for air to glass interface then an unpolarised light is incident on a glass (n = 1.5), such that reflected and refracted rays are perpendicular to each other, is nearly:
Answer & explanation
Correct answer: option 3
The correct answer is option (3) : $i_B=57°$
From Brewster’s law
$tan(i_B)=\mu $
$i_B=tan^{-1}(1.5)≈57°$