Practicing Success
The Brewster’s angle for air to glass interface then an unpolarised light is incident on a glass (n = 1.5), such that reflected and refracted rays are perpendicular to each other, is nearly: |
$i_B=30°$ $i_B=45°$ $i_B=57°$ $i_B=47°$ |
$i_B=57°$ |
The correct answer is option (3) : $i_B=57°$ From Brewster’s law $tan(i_B)=\mu $ $i_B=tan^{-1}(1.5)≈57°$ |