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Practicing Success
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The maximum value of $f(x) = 2x^3 – 21x^2 + 36x + 7$ is |
at x = 2 at x = 1 at x = 6 at x = 3 |
at x = 1 |
$f' (x) = 6x^2 – 42 x + 36$ $f''(x) = 12x – 42$ Hance $f' (x) = 0\, 6(x^2 – 7x + 6) = 0$ $x = 1 , 6$ $f'' (a) = 12 – 42 = –30 < 0$ f(x) has a maximum at x = 1 |
