The figure below shows a part of an electric circuit. The current marked $I_A$ is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 1.3 A
Using Kirchoff's current law,
$(0.2+0.2+I_A)A=(1.2+0.5)A$
$⇒I_A=(1.7-0.4)A$
$⇒I_A=1.3A$