If $m+\frac{1}{m-2}=4$, then find the value of $(m-2)^2+\frac{1}{(m-2)^2}$.
Answer & explanation
Correct answer: option 4
If $m+\frac{1}{m-2}=4$
Subtract -2 on both the sides
If $m - 2 +\frac{1}{m-2}=4 - 2$
If $m - 2 +\frac{1}{m-2}=2$
Then the value of $(m-2)^2+\frac{1}{(m-2)^2}$ = 22 - 2 = 2