Two concentric circles are of radii 13 cm and 5 cm. The length of the chord of the larger circle which touches the smaller circle is:
Answer & explanation
Correct answer: option 1
We know that,
Hypotensue2 = Base2 + Perpendicular2
OM = 5
OP = 13
In ΔOPM
(OP)2 = (OM)2 + (PM)2
= 132 = 52 + (PM)2
= (PM)2 = 169 - 25
= PM = \(\sqrt {144}\)
= PM = 12
Now,
PQ = 2PM
= PQ = 2 × 12
= PQ = 24 cm