Match List-I with List-II.
|
List-I (Function) |
List-II (Interval in which function is increasing) |
|
(A) $\frac{x}{\log_ex}$ |
(I) $(-∞,-2) (2,∞)$ |
|
(B) $\frac{x}{2}+\frac{2}{x},x≠0$ |
(II) $\left(-\frac{\pi}{4},\frac{\pi}{4}\right)$ |
|
(C) $x^x, x>0$ |
(III) $\left(\frac{1}{e},∞\right)$ |
|
(D) $\sin x – \cos t$ |
(IV) $(e, ∞)$ |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → (A)-(IV), (B)-(I), (C)-(III), (D)-(II)
(A) $f(x)=\frac{x}{\log_ex}$
$f'(x)=\frac{\log_ex-1}{(\log_ex)^2}$
for $f(x)$ to be increasing, $f'(x)>0$
$⇒\log_ex-1>0$
$⇒\log_ex>1$
$⇒x>e$
$⇒x∈(e, ∞)$ (IV)
(B) $f(x)=\frac{x}{2}+\frac{2}{x}=\frac{x^2+4}{2x}$
$f'(x)=\frac{(2x)(2x)-(x^2+4)(2)}{4x^2}$
$=\frac{4x^2-2x^2-8}{4x^2}=\frac{2x^2-8}{4x^2}$
$=\frac{x^2-4}{2x^2}$
$f'(x)>0$
$⇒x^2-4>0$
$⇒x>2,x<-2$
$⇒x∈(-∞,-2) (2,∞)$ (I)
(C) $f(x)=x^x$
$f'(x)=x^x+x^x.\log(x)$
$=x^x(1+\log (x))$
$⇒1+\log (x)>0$
$⇒\log (x)>-1$
$⇒x>\frac{1}{e}$
$⇒x∈\left(\frac{1}{e},∞\right)$ (III)
(D) $f(x)=\sin x-\cos t$
$f'(x)=\cos x$
$⇒\cos x>0$
$⇒x∈\left(-\frac{\pi}{4},\frac{\pi}{4}\right)$ (II)