Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Ratios

Question:

If a : b = 3 : 2, then find the value of \(\frac{5a+2b }{3a+4b}\)

Options:

\(\frac{19}{17}\)

\(\frac{17}{19}\)

\(\frac{29}{21}\)

19

Correct Answer:

\(\frac{19}{17}\)

Explanation:

a : b   =  3 : 2

\(\frac{5a\;+\;2b }{3a\;+\;4b}\)= \(\frac{5×3\;+\;2×2 }{3×3\;+\;4×2}\)  = \(\frac{19}{17}\)