An airliner is flying due east from the USA to France. The Earth's magnetic field acts at $60^{\circ}$ to the horizontal and has a strength of $\sqrt{3} \times 10^{-4} T$, and the aircraft speed is $300 ms^{-1}$. The wing span of the aircraft is 60 m. The potential difference induced between the tips of the wings is:

2.7 V

The correct answer is Option (1) → 2.7 V

B, strength of magnetic field = $\sqrt{3}×10^{-4}$

v, speed of the aircraft = 300 m/s

L, Wingspan of the aircraft = 60 m

θ, angle between the magnetic field and plane = 60°

ε,  induced emf = $ε=BvL\sin(θ)$ [formula]

$=\sqrt{3}×10^{-4}×300×60×\frac{\sqrt{3}}{2}$

$=3×10^{-4}×300×60×\frac{1}{2}$

$=\frac{5.4}{2}$

$=2.7V$