In ΔABC, AD is median and G is the point on AD such that AG : GD = 2 : 1, then area (ΔABG) : area (ΔABC) is equal to?

1 : 3

G is centroid

So, area of ΔABG = area of ΔBGC = area of ΔAGC

Let area of each Δ = 1 Unit²

area of ΔABC = ΔABG + area of ΔBGC + area of ΔAGC = 3

area of (ΔABG) : area of (ΔABC)

           1          :          3