CUET Preparation Today
The maximum value of $y=x^3-3 x$ is: |
2 at x = 1 2 at x = -1 0 at x = 0 0 at x = 3 |
2 at x = -1 |
The correct answer is Option (2) → 2 at x = -1 $y=x^3-3 x$ $y'=3x^2-3=0⇒x=±1$ $y''=6x$ $y''(-1)=-6<0$ (point of maxima) $y_{max}=(-1)^3-3(-1)=2$ |
