The slope of the stopping potential $V_0$ versus frequency $v$ of the incident radiation plot is
(Where symbols have their usual meaning)
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $h/e$
Photoelectric effect equation:
$e V_0 = h \nu - \phi$
Rewriting:
$V_0 = \frac{h}{e} \nu - \frac{\phi}{e}$
This is in the form of a straight line: $V_0 = \text{slope} \cdot \nu + \text{intercept}$
Therefore, slope of $V_0$ versus $\nu$ plot:
Slope $= \frac{h}{e}$