CUET Preparation Today
The work function of calcium is 2.14 eV. Find the threshold frequency for calcium. |
$5.16 × 10^{12} Hz$ $5.16 × 10^{13} Hz$ $5.16 × 10^{14} Hz$ $5.16 × 10^{15} Hz$ |
$5.16 × 10^{14} Hz$ |
The correct answer is Option (3) → $5.16 × 10^{14} Hz$ The threshold frequency $(V_0)$ is, Work function, $\phi=hv_0$ $⇒v_0=\frac{\phi}{h}=\frac{3.43×10^{-19}}{6.626×10^{-34}}$ $=5.16×10^{14}Hz$ |
