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Determine the value of k for which the function $f(x)=\left\{\begin{array}{cc}\frac{x^2-9}{x-3} & , x \neq 3 \\ k & , x=3\end{array}\right.$ is continuous at x = 3 |
6 -6 3 0 |
6 |
The correct answer is Option (1) → 6 $f(3)=k$ $\underset{x→3}{\lim}\frac{x^2-9}{x-3}=\underset{x→3}{\lim}x+3=6$ so (k = 3) as f is continuous at $x=3$ |
