Practicing Success
Practicing Success
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Consider the system of linear equations: $x_1+2x_2 + x_3 = 3$ $2x_1 + 3x_2 + x_3 = 3$ $3x_1+5x_2 + 2x_3 =1$ The system has |
a unique solution no solution infinite number of solutions exactly three solutions |
no solution |
We have, $D=\begin{vmatrix}1&2&1\\2&3&1\\3&5&2\end{vmatrix}=0$ and $D_1=\begin{vmatrix}3&2&1\\3&3&1\\1&5&2\end{vmatrix}≠0$ So, the given system of equations has no solution. |
