The area of the region bounded by the curve $y^2=x$ and the lines $x=1, x=4 $ is :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{28}{3}sq.units$
By symmetry
Area (I) = Area (II)
⇒ Area = $2×\int\limits_1^4\sqrt{x}dx$
$=\left[2×\frac{2}{3}x^{\frac{3}{2}}\right]_1^4$
$=\frac{4}{3}(8-1)=\frac{28}{3}sq.units$