A reaction was found to be second-order with respect to the concentration of carbon monoxide. If the concentration of carbon monoxide is doubled, with everything else kept the same, the rate of reaction will
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → Increase by a factor of 4
For a reaction that is second order in CO, the rate is proportional to the square of [CO]:
\( \displaystyle \text{Rate}=k[\ce{CO}]^2 \)
\( \displaystyle \text{Rate}'=k(2[\ce{CO}])^2=4k[\ce{CO}]^2 \)
\( \displaystyle \frac{\text{Rate}'}{\text{Rate}}=2^2=4 \)