In the Figure in △PQR, PT ⊥ QR at T and PS is the bisector of ∠QPR. If ∠PQR = 78°, and ∠TPS = 24° then the measure of ∠PRQ is
Answer & explanation
Correct answer: option 3
As we know,
\(\angle\)TPS = (\(\angle\)TQP - \(\angle\)PRQ)/2
24 = (78 - \(\angle\)PRQ)/2
78 - \(\angle\)PRQ = 24 x 2 = 48
\(\angle\)PRQ = 78 - 48 = \({30}^\circ\)