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If $y =log_2(log_2x),$ then $\frac{dy}{dx}$ is equal to : |
$\frac{log_2e}{log_ex}$ $\frac{log_2e}{xlog_e2}$ $\frac{log_2e}{xlog_ex}$ $\frac{log_ex}{xlog_2e}$ |
$\frac{log_2e}{xlog_ex}$ |
The correct answer is Option (3) → $\frac{log_2e}{xlog_ex}$ $y =\log_2(\log_2x)=\frac{\log(\log_2x)}{\log 2}$ $y=\frac{\log(\log x)}{\log_2}-\frac{\log(\log_2)}{\log_2}$ $\frac{dy}{dx}=\frac{1}{x\log_2\log x}=\frac{\log_2e}{x\log x}$ |
