For two events A, B $P(A ∪ B) = \frac{7}{12}, P(A) = \frac{5}{12}, P(B) = \frac{3}{12}$ Then P(A ∩ B) =

$\frac{1}{2}$ $\frac{1}{12}$ $\frac{1}{6}$ $\frac{1}{3}$

$\frac{1}{12}$

$P(A ∪ B) = \frac{7}{12}, P(A) = \frac{5}{12}, P(B) = \frac{3}{12}$ so P(A ∪ B) = P(A) + P(B) - P(A ∩ B) ⇒ P(A ∩ B) = P(A) + P(B) - P(A ∪ B) = $\frac{3}{12} + \frac{5}{12} - \frac{7}{12}$ = $\frac{1}{12}$