For two events A, B P(A ∪ B) = 7/12, P(A) = 5/12, P(B) = 3/12 Then P(…

$P(A ∪ B) = \frac{7}{12}, P(A) = \frac{5}{12}, P(B) = \frac{3}{12}$

so P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

⇒ P(A ∩ B) = P(A) + P(B) - P(A ∪ B)

= $\frac{3}{12} + \frac{5}{12} - \frac{7}{12}$

= $\frac{1}{12}$