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The value of $tan^{-1}\frac{2}{11}+tan^{-1}\frac{7}{24}$ is : |
$tan^{-1}\frac{1}{2}$ $tan^{-1}2$ $tan^{-1}\frac{1}{3}$ $tan^{-1}3$ |
$tan^{-1}\frac{1}{2}$ |
The correct answer is Option (1) → $\tan^{-1}\frac{1}{2}$ $\tan^{-1}\frac{2}{11}+\tan^{-1}\frac{7}{24}$ $=\tan^{-1}\left(\frac{\frac{2}{11}+\frac{7}{24}}{1-\frac{2×7}{11×24}}\right)$ $=\tan^{-1}\frac{1}{2}$ |
