The value of $tan^{-1}\frac{2}{11}+tan^{-1}\frac{7}{24}$ is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\tan^{-1}\frac{1}{2}$
$\tan^{-1}\frac{2}{11}+\tan^{-1}\frac{7}{24}$
$=\tan^{-1}\left(\frac{\frac{2}{11}+\frac{7}{24}}{1-\frac{2×7}{11×24}}\right)$
$=\tan^{-1}\frac{1}{2}$