In a triangle MNO, XA, XB and XC are perpendicular bisectors on sides MN, ON and OM respectively intersect each other at X. If ∠NMO = 55 degree, then what is the value of ∠NXO?

110 degree

∠NMO = 55° 

We have a concept =If O is the circumcenter of the △ABC then the angle made at the circumcenter by joining any two vertices of the triangle is twice the angle at the third vertex of the triangle.

So, ∠NXO = 2 × ∠NMO

∠NXO = 2 × 55°

∠NXO = 110°