If $\frac{\sin ^2 ∅-3 \sin ∅+2}{\cos ^2 ∅}=1$, where $0^{\circ}<∅<90^{\circ}$, then what is the value of $(\cos 2 ∅-\sin 3 ∅+cosec 2 ∅) ?$

$\frac{-3-4 \sqrt{3}}{6}$ $\frac{-3+4 \sqrt{3}}{6}$ $\frac{3+4 \sqrt{3}}{6}$ $\frac{3-4 \sqrt{3}}{6}$

$\frac{-3+4 \sqrt{3}}{6}$