Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

Find the value of \(\frac{cosec90°\;+\;cos45°}{sin90°\;+\;cot45°\;+\; tan45° }\)

Options:

 \(\frac{2+\sqrt {2}}{5}\)

 \(\frac{2+\sqrt {2}}{4}\)

 \(\frac{2+\sqrt {2}}{3}\)

 \(\frac{2+\sqrt {2}}{6}\)

Correct Answer:

 \(\frac{2+\sqrt {2}}{6}\)

Explanation:

⇒ \(\frac{cosec90°\;+\;cos45°}{sin90°\;+\;cot45°\;+\; tan45°}\)

= \(\frac{1+\frac{1}{\sqrt {2}}}{1+1 + 1}\)

= \(\frac{\sqrt {2}+1}{3\sqrt {2}}\)

= \(\frac{\sqrt {2}+1}{3\sqrt {2}}\)×\(\frac{\sqrt {2}}{\sqrt {2}}\)

\(\frac{2+\sqrt {2}}{6}\)