Practicing Success
Practicing Success
CUET Preparation Today
The function $f(x)= 2x^3-3x^2-12x+4$ has : |
two points of local maximum two points of local minimum one maximum and one minimum no maximum and no minimum |
one maximum and one minimum |
The correct answer is option (3) → one maximum and one minimum $f(x)= 2x^3-3x^2-12x+4$ $f'(x)= 6x^2-6x-12=0$ $x^2-x-2=0$ $⇒x=-1,2$ $f''(x)=12x-6$ $f''(-1)=-18$ point of maxima $f''(2)=18$ point of minima |
