Practicing Success
Practicing Success
CUET Preparation Today
Let f(x) = [tan2x], where [.] denotes the greatest integer function. Then |
$\underset{h→0}{\lim}$ f(x) doesn’t exist f(x) is continuous at x = 0 f(x) is not differentiable at x = 0 f'(0) = 1 |
f(x) is continuous at x = 0 |
$\underset{h→0}{\lim}[tan^2(0+h)]=\underset{h→0}{\lim}[tan^2(0-h)]=[tan^20]=0$ ⇒ f(x) is continuous at x = 0. Since f(x) = 0 in the neighbourhood of 0, f'(0) = 0. Hence (B) is the correct answer. |
