Practicing Success
Practicing Success
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If cot B = 9, then what will be the value of sec2 B? |
98/81 92/81 42/81 82/81 |
82/81 |
cotB = \(\frac{9}{1}\) B = 9 , P = 1 Using pythagoras theorem P2 + B2 = H2 12 + 92 = H2 H2 = 82 sec2B = \(\frac{82}{81}\) |
