If cot B = 9, then what will be the value of sec2 B?
Answer & explanation
Correct answer: option 4
cotB = \(\frac{9}{1}\)
B = 9 , P = 1
Using pythagoras theorem
P2 + B2 = H2
12 + 92 = H2
H2 = 82
sec2B = \(\frac{82}{81}\)
If cot B = 9, then what will be the value of sec2 B?
Correct answer: option 4
cotB = \(\frac{9}{1}\)
B = 9 , P = 1
Using pythagoras theorem
P2 + B2 = H2
12 + 92 = H2
H2 = 82
sec2B = \(\frac{82}{81}\)