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-- Mathematics - Section B1
Three-dimensional Geometry
Solution of the inequality |2x| ≥ |8-2x| is
(-∞, -2]
[-2, ∞)
[2, ∞)
(-∞, 2)
|2x| ≥ |8-2x| Squaring both side.
(2x)2 ≥ (8-2x)2
⇒ 4x2 ≥ 64 + 4x2 - 32x
⇒ 32x ≥ 64
⇒ x ≥ 2
⇒ x ∈ [2, ∞)